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(1-t)=3t^2-5t+26
We move all terms to the left:
(1-t)-(3t^2-5t+26)=0
We add all the numbers together, and all the variables
(-1t+1)-(3t^2-5t+26)=0
We get rid of parentheses
-3t^2-1t+5t+1-26=0
We add all the numbers together, and all the variables
-3t^2+4t-25=0
a = -3; b = 4; c = -25;
Δ = b2-4ac
Δ = 42-4·(-3)·(-25)
Δ = -284
Delta is less than zero, so there is no solution for the equation
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